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Nernst Equation

In the Daniel...

Question

In the Daniel cell, which of the following changes increases the cell EMF?

A

Increasing the concentration of

Z n S O_{4}

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B

Increasing the dilution of

Z n S O_{4}

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C

Decreasing the concentration of

C u S O_{4}

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D

Increasing the dilution of

C u S O_{4}

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Solution

The correct option is B Increasing the dilution of $Z n S O_{4}$
$Z n + C u^{2 +} \to Z n^{2 +} + C u$
$E_{c e l l} = E_{c e l l}^{\circ} - \frac{R T}{n F} l o g (\frac{Z n^{2 +}}{C u^{2 +}})$
As for $E_{c e l l}$ to increase, $l o g (\frac{Z n^{2 +}}{C u^{2 +}})$ should decrease.

$∴ \frac{[Z n^{2 +}]}{[C u^{2 +}]}$ should decrease.

$∴$ Either concentration of $C u S O_{4}$ should increase or concentration of $Z n S O_{4}$ should decrease.
As the concentration of $Z n S O_{4}$ decreases, its dilution increases.
Hence, option B is correct.

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Similar questions

Q. The emf of Daniell cell at

298 K

E_{1} Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) | C u

When the concentration of

Z n S O_{4}

1.0 M

C u S O_{4}

0.01 M

, the emf changed to

E_{2}

What is the relation between

E_{1}

E_{2}

?

Q. Calculate the EMF of a Daniel cell when the concentration of

Z n {S O}_{4}

C u {S O}_{4}

are 0.001 M and 0.1 respectively. The standard potential of the cell is 1.1 V.

Q. In the electrochemical cell:

Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) C u

, the emf of this Daniell cell is

E_{1}

. When the concentration of

Z n S O_{4}

is changed to 1.0 M and that of

C u S O_{4}

changed to 0.01 M, the emf changes to

E_{2}

. From the followings, which one is the relationship between

E_{1}

E_{2}

? (Given, RT/F = 0.059)

Q. Two students use same stock solution of

Z n S O_{4}

and a solution of

C u S O_{4}

. The emf of one cell is

0.03 V

higher than that of other. The concentration of

C u S O_{4}

in the cell with higher emf value is

0.5 M

. Find out the concentration of

C u S O_{4}

in the other cell.

(\frac{2.303 R T}{F} = 0.06)

Q. In the electrochemical cell:

Z n | Z n S O_{4} (0.01 M) | | C u S O_{4} (1.0 M) | C u

, the emf of this Daniel cell is

E_{1}

. When the concentration of

Z n S O_{4}

1.0 M

C u S O_{4}

0.01 M

, the emf changes to

E_{2}

. From the followings, which one is the relationship between

E_{1}

E_{2}

\frac{R T}{F} = 0.059)

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