Question

In the decay sequence, ${}_{92}^{238}U\stackrel{-x_1}{\to }{}_{90}^{234}Th\stackrel{-x_2}{\to }{}_{91}^{234}Pa\stackrel{-x_3}{\to }{}^{234}Z\stackrel{-x_4}{\to }{}_{90}^{230}Th$

$x_1,x_2,x_3$ and $x_4$, are particle/ radiation emitted by the respective isotopes.

The correct option(s) is (are)

• A. $x_1$ will deflect towards negatively charged plate
• B. $x_2$ is ${\beta }^{-}$
• C. $x_3$ is $\gamma -ray$
• D. $z$ is an isotope of uranium

Answer 1

Answer: (A), (B), (D)

The correct options are
A $x_1$ will deflect towards negatively charged plate
B $x_2$ is ${\beta }^{-}$
D $z$ is an isotope of uranium

${}_{92}^{238}U\stackrel{{-}_{2}H{e}^4}{\to }{}_{90}^{234}Th\stackrel{{-}_{-1}{e}^o}{\to }{}_{91}^{234}Pa\stackrel{{-}_{-1}{e}^o}{\to }{}_{92}^{234}Z\stackrel{{-}_{2}H{e}^4}{\to }{}_{90}^{230}Th$

$x_1=\alpha$ since positively charged so, will attracted by negative plate.
$x_2=\beta$ negatively charged and attracted by positive plate
$x_3=\beta$ negatively charged and attracted by positive plate
$x_4=\alpha$ since positively charged so, will attracted by negative plate.

U and Z have the same atomic number so they are isotope.