In the detection test of carbon and hydrogen with cupric oxide, carbon is oxidized to :

carbon monoxide

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carbon dioxide

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carbonic acid

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copper sulphate

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Solution

The correct option is B carbon dioxide
The given organic compound is mixed with dry copper oxide ( $C u O$ ) and heated in a hard glass tube. The products of the reaction are passed over (white) anhydrous copper sulphate and then bubbled through lime water. If copper sulphate turns blue due to the formation of $C u S O_{4} .5 H_{2} O$ (by water vapor) then the compound contains hydrogen. If lime water is turned milky by $C O_{2}$ , then the compound contains carbon.So, the carbon is oxidized to $C O_{2}$ .

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Similar questions

Describe giving all practical details, how would you prepare :

(a) copper sulphate crystals from a mixture of charcoal and black copper oxide,

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(d) Calcium sulphate from calcium carbonate.

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