CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In the diagram shown, a light ray is incident on the lower medium boundary at an angle 45 with the normal. Light ray become tangential to the top part of medium2 after all kind of refraction for μ2>2. Which of the following statements is/are true?


A
If μ2>2 then angle of deviation is 45.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
If μ2<2 then angle of deviation is 90.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
If μ2<2 then angle of deviation is 135.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
If μ2>2 then angle of deviation is 0.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B If μ2<2 then angle of deviation is 90.

Critical angle is given by
θc=sin1(μ2μ1)=sin1(μ22)

If μ2<2, then total internal reflection takes place and that ray reflects back, the angle of deviation is
180(45+45)=90

If μ=2, then the ray passes tangentially at the first medium, the angle of deviation is 180(45+90)=45

If μ>2, then the ray enters the second medium and, grazes the interface of medium2 & 3 as shown in figure.

So, the angle of refraction is 90 in medium 3.

The deviation is 180(45+90)=45.

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image