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Electrolytes- Strong,Weak

In the electr...

Question

In the electrolysis of $H_{2} O$ , 11.2 litre of $H_{2}$ liberated at cathode at STP. How much $O_{2}$ will be liberated at anode under the same conditions?

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Solution

$H_{2} O E l e c t r o l y s i s - ------ \to H_{2} + \frac{1}{2} O_{2}$
The ratio of $H_{2} : O_{2}$ is $1 : 0.5$ or $2 : 1$
$2$ volumes of $H_{2}$ & $1$ volume of $O_{2}$ gas is obtained.
Given $11.2 L$ of $H_{2}$ is liberated at cathode.
$∴$ Volume of $O_{2} = \frac{11.2}{2} = 5.6 L$ at anode.

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Electrolytes- Strong,Weak

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