In the equation ax - by - c -0- if y - cx - d - b and a - d- thenA- x -1B- x-1C- x-2D- x-3

The correct option is B x = 1Given that, a = d and nbsp; y nbsp; = cx+d/b Now, substituting nbsp; the given values of y and a in ax + by + c = 0, ⇒dx + ...

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Standard IX

Mathematics

Solving Equations Using Method of Substitution

In the equati...

Question

In the equation $a x + b y + c = 0$ , if
$y = \frac{c x + d}{b}$ and $a = d$ , then .

x = 1

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x = - 1

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x = 2

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x = - 3

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Solution

The correct option is B $x = - 1$
Given that,
$a = d$ and $y = \frac{c x + d}{b}$

Now, substituting the given values of $y$ and $a$ in $a x + b y + c = 0,$
$\Rightarrow d x + (c x + d) + c = 0$
$\Rightarrow (c + d) x + (c + d) = 0$
$\Rightarrow x = - \frac{(c + d)}{(c + d)}$
$\Rightarrow x = - 1$

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Similar questions

In the equation ax+by+c=0, if $y = \frac{(c x - d)}{b}$ then x =

In the equation $a x + b y + c = 0$ , if y= $\frac{(c x + d)}{b}$ and a = d, then what is the value of ' $x$ ' ?

Q. Assertion (A): The joint equation of lines

y = x

and

y = - x

y^{2} = - x^{2}

i.e.

x^{2} + y^{2} = 0.

Reason (R):The joint equation of lines

a x + b y = 0

and

c x + d y = 0.

(a x + b y) (c x + d y) = 0

where

a, b, c, d

are constants.

In the equation ax+by+c=0, if y= $\frac{(c x + d)}{b}$ then x =

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In the equation ax+by+c=0, if y=cx+db and a=d, then .

The correct option is B x=−1Given that, a=d and y=cx+db Now, substituting the given values of y and a in ax+by+c=0, ⇒dx+(cx+d)+c=0 ⇒(c+d)x+(c+d)=0 ⇒x=−(c + d)(c + d) ⇒x=−1

In the equation $a x + b y + c = 0$ , if
$y = \frac{c x + d}{b}$ and $a = d$ , then .

The correct option is B $x = - 1$
Given that,
$a = d$ and $y = \frac{c x + d}{b}$

Now, substituting the given values of $y$ and $a$ in $a x + b y + c = 0,$
$\Rightarrow d x + (c x + d) + c = 0$
$\Rightarrow (c + d) x + (c + d) = 0$
$\Rightarrow x = - \frac{(c + d)}{(c + d)}$
$\Rightarrow x = - 1$