Question

In the equation $ax+by+c=0$, if y= $\frac{(cx+d)}{b}$ and a = d, then what is the value of '$x$' ?

• A. -1
• B. -2
• C. $\frac{(d+c)}{(a+c)}$
• D. $\frac{(-d+c)}{(a+c)}$

Answer 1

The correct option is A

-1

Putting the given values of y and a in $ax+by+c=0,$
$dx+(cx+d)+c=0$
$\Rightarrow (c+d)x+(c+d)=0$
$\Rightarrow x=-\frac{(c+d)}{(c+d)}=-1$