Question

In the equation $ax+by+c=0$, if $y=\frac{(cx+d)}{b}$ then $x=$

• A. $\frac{a+c}{d+c}$
• B. $\frac{b+c}{d+c}$
• C. $\frac{-d-c}{a+c}$
• D. $\frac{d+c}{a+c}$

Answer 1

The correct option is C

$\frac{-d-c}{a+c}$

Given $ax+by+c=0$,

Also given $y=\frac{(cx+d)}{b}$,

substitute this in $ax+by+c=0$

$\Rightarrow ax+\left[b\frac{(cx+d)}{b}\right]+c=0$

$\Rightarrow ax+cx+d+c=0$

$\Rightarrow (a+c)x=-d-c$

$\therefore x=\frac{-d-c}{a+c}$