In the equation a x-b y-c-0if y - cx - d - band a - d-then what is the value of X -A- -1B- -2C- d-c-a-cD- -d-c-a-c

The correct option is A 1Given, nbsp; nbsp;y = (cx + d)/b and a = d Putting the given values of y and a in ax + by + c = 0, dx + b(cx + d/b) + c = 0 dx ...

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Standard IX

Mathematics

Substitution Method

In the equati...

Question

In the equation
$a x + b y + c = 0$ ,
$if y = \frac{(c x + d)}{b}$
and a = d,
then what is the value of $x$ ?

-1

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-2

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\frac{(d + c)}{(a + c)}

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\frac{(- d - c)}{(a + c)}

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Solution

The correct option is A -1
Given,
$y = \frac{(c x + d)}{b} and a = d$

Putting the given values of
$y$ and $a$ in $a x + b y + c = 0,$
$d x + b (\frac{c x + d}{b}) + c = 0$
$d x + c x + d + c = 0$
$\Rightarrow (c + d) x + (c + d) = 0$
$\Rightarrow x = - \frac{(c + d)}{(c + d)} = - 1$

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In the equation ax+by+c=0, if y=(cx+d)b and a = d, then what is the value of x ?

The correct option is A -1Given, y=(cx+d)b and a=d Putting the given values of y and a in ax+by+c=0, dx+b(cx+db)+c=0 dx+cx+d+c=0 ⇒(c+d)x+(c+d)=0 ⇒x=−(c+d)(c+d)=−1

In the equation
$a x + b y + c = 0$ ,
$if y = \frac{(c x + d)}{b}$
and a = d,
then what is the value of $x$ ?

The correct option is A -1
Given,
$y = \frac{(c x + d)}{b} and a = d$

Putting the given values of
$y$ and $a$ in $a x + b y + c = 0,$
$d x + b (\frac{c x + d}{b}) + c = 0$
$d x + c x + d + c = 0$
$\Rightarrow (c + d) x + (c + d) = 0$
$\Rightarrow x = - \frac{(c + d)}{(c + d)} = - 1$