In the equation- MnO4-H-ne- Mn2-H2O- the value of n is -

The correct option is A 5Balance equation is: MnO_4^ +8H^++5e^ → Mn^2++4H_2O So, n = 5. ...

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Magnetic Properties

In the equati...

Question

In the equation, $M n O_{4}^{-} + H^{+} n e^{-} \to M n^{2 +} + H_{2} O,$ the value of n is :

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M n O_{4}^{-} + 8 H^{+} + n e^{-} ⟶ M n^{2 +} + 4 H_{2} O

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} ⟶ M n^{2 +} + C O_{2} + H_{2} O$ the reductant is

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?

{M n O_{4}}^{-} + H^{+} + H_{2} O_{2} \to M n^{2 +} + H_{2} O + O_{2}

C r_{2} O_{7}^{2 -} + H^{+} + I^{-} \to C r^{3 +} + I_{2} + H_{2} O

C r_{2} O_{7}^{2 -} + F e_{2}^{+} + H^{+} \to C r^{3 +} + F e^{3 +} + H_{2} O

M n O^{4 -} + S O_{3}^{2 -} + H^{+} \to M n^{2 +} + S O_{4}^{2 -} + H_{2} O

M n O^{4 -} + H^{+} + B r^{-} \to M n^{2 +} + B r_{2} + H_{2} O

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