In the equilibrium $4 H_{2} O (g) + 3 F e (s) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)$ , the yield of $H_{2}$ can be increased by:

increasing the pressure

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passing more steam

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increasing the mass of iron

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decreasing the pressure

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Solution

The correct option is B passing more steam
The equilibrium reaction is $4 H_{2} O (g) + 3 F e (s) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)$ . When more steam is passed, the equilibrium shifts in the forward direction so that more steam is consumed in the reaction which nullifies the effect of passing more steam. Due to this, more hydrogen is obtained.

Thus, the yield of hydrogen can be increased by passing more steam.

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Similar questions

Q. In the equilibrium

4 H_{2} O_{(g)} + 3 F e_{(s)} ⇌ F e_{3} O_{4 (s)} + 4 H_{2 (s)}

the yield of

H_{2}

can be increased by:

3 F e_{(s)} + 4 H_{2} O_{(g)} ⇌ F e_{3} O_{4 (s)} + 4 H_{2 (g)} +

heat. Which of the following effects disturb the system from equilibrium?

Q. For the equilibrium reaction

3 F e (s) + 4 H_{2} O (g) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)

, the relationship between

K_{p}

and

K_{c}

is:

Q. Equilibrium constant of a reaction,

3 F e (s) + 4 H_{2} O_{(g)} ⇌ F e_{3} O_{4} (s) + 4 H_{2 (g)}

is same whether, the reaction is carried out in an open vessel or a closed vessel.

Does the number of moles of reaction products increase, decrease or remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?

(a)

(b)

(c)

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In the equilibrium 4H2O(g)+3Fe(s)⇋Fe3O4(s)+4H2(g), the yield of H2 can be increased by:

In the equilibrium $4 H_{2} O (g) + 3 F e (s) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)$ , the yield of $H_{2}$ can be increased by: