In the equilibrium $4 H_{2} O_{(g)} + 3 F e_{(s)} ⇌ F e_{3} O_{4 (s)} + 4 H_{2 (s)}$ the yield of $H_{2}$ can be increased by:

increasing the pressure

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passing more steam

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increasing the mass of iron

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decreasing the pressure

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Solution

The correct option is C increasing the pressure
$4 H_{2} O + 3 F e ⇌ {F e}_{3} O_{4} + 4 H_{2}$
The yield of $H_{2}$ can be increased by increasing the pressure as increase in pressure shifts the reaction to the side which has lesser number of moles.

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Similar questions

4 H_{2} O (g) + 3 F e (s) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)

H_{2}

3 F e_{(s)} + 4 H_{2} O_{(g)} ⇌ F e_{3} O_{4 (s)} + 4 H_{2 (g)} +

3 F e (s) + 4 H_{2} O (g) ⇋ F e_{3} O_{4} (s) + 4 H_{2} (g)

K_{p}

K_{c}

3 F e + 2 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

3 F e (s) + 4 H_{2} O_{(g)} ⇌ F e_{3} O_{4} (s) + 4 H_{2 (g)}

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