wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the expansion (1+x)5=1+5x+ax2......x5, find the value of a

___

Open in App
Solution

We can solve this if we know the binomial expansion of (1+x)5
.

Binomial expansion of (a+b)n is (a+b)n=an+nc1an1b+nc2an2b2+....bn

(1+x)5=1+5c1x+5c2x2.......5c5x5

a=5c2=5!3!×2!=10


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon