In the expansion of a-x-b x12- the coefficient of x-10 will beA- 12 a11 b11B- 12 a11C- 12 b11 aD- 12 a11 b

The correct option is D T_r+1=12_c_r ( a/x )^12 r ( bx )^r =12_c_r.a^12 r.b^r.x^2r 12 ∴ 2x 12= 10 ⇒ r=1 ∴coefficient=12.a^11.b ...

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Binomial Coefficients

In the expans...

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In the expansion of ( $\frac{a}{x} + b x)^{12}$ , the coefficient of $x^{- 10}$ will be

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