In the expansion of (3x−1x2)10, the 5th term from the end is
A
16486x8
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B
17010x8
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C
13486x8
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D
None of these
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Solution
The correct option is B17010x8 There are 11 terms in the expansion of (3x−1x2)10 Therefore, 5th term from the end. =(10−5+2)th term from beginning =T7=10C6(3x)10−6(−1x2)6 =10!6!4!34x41x12