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Question

In the expansion of (3x1x2)10, the 5th term from the end is

A
16486x8
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B
17010x8
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C
13486x8
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D
None of these
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Solution

The correct option is B 17010x8
There are 11 terms in the expansion of (3x1x2)10
Therefore, 5th term from the end.
=(105+2)th term from beginning
=T7=10C6(3x)106(1x2)6
=10!6!4!34x41x12
=17010x8

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