In the fig. AB, AC and PQ are tangents. given,PQ = 8 cm, AQ = 9 cm and PA = 7 cm, then find AC.
12 cm
Here, AB = a + y , AC = b + x , PQ = PR + RQ = x + y
Perimeter of △APQ=AQ+PQ+AP=a+y+x+b=AB+AC=2AC
AC = AB ( Tangent from an external point are equal )
2 AC = Perimeter of △APQ = 8 + 9 +7 = 24 cm
AC = 12 cm