Question

In the figure a potential of +1200 V is given to point A and point B is earthed,what is the potential at the point P

• A. 100 V
• B. 200 V
• C. 400 V
• D. 600 V

Answer 1

The correct option is C 400 V

Potential of $=+1200V$

Point $A$ and point $B$ is earthed $R_0$ at point $P$,

equivalent capacitance, $\frac{(4+2)\times 3}{6+3}=\frac{6\times 3}{9}=2\mu F$

Now, $V_P$ at point $P$ $=V_P=1200\times \frac{1}{3}=400V$

$V_P$ is passing through only $3\mu F$.