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Gravitational Potential Energy

In the figure...

Question

In the figure a potential of 1200V is given to point A and point B is earthed, what is the potential at the point P?

100V

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200V

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400V

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800V

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Solution

The correct option is
C

400V

$3 μ F$ and $6 μ F$ are connected in series
$q_{3} = q_{6}$
$C_{1} V_{1} = C_{2} V_{2}$
$3 (1200 - V_{P}) = 6 (V_{P} - V_{B})$
$V_{B} = 0$ [Grounded]
$1200 - V_{P} = 2 V_{P}$
$3 V_{P} = 1200$
$V_{P} = 400 V$

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