In the figure, AB is parallel to CD, if ∠1 + ∠3 = 240°, then find the value of ∠6.
Given that ∠1 + ∠3 = 240°
Also, ∠1 = ∠3 [Vertically opposite angles]
Therefore, 2∠3 = 240°
∠3 = 120°
Since ∠3 and ∠6 are co-interior angles,
∠3 + ∠6 = 180°
∠6 = 180° - 120° = 60°