Question

In the figure, ABC is an equilateral triangle and BCDE is a square. The $\angle$ EAD is

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

The correct option is D

AC = BC (Since $\Delta$ ABC is equilateral.)
$\angle$ DCA = ${90}^{\circ }+{60}^{\circ }={150}^{\circ }$
$\angle$ DAC = $\angle$ CDA (Since AC and CD are equal)
So, $\angle$ DAC = $\frac{180-150}{2}=\frac{30}{2}={15}^{\circ }$
Similarly $\angle$ EAB = ${15}^{\circ }$
So, $\angle$ EAD = (60-15-15)=${30}^{\circ }$