In the figure, $A B C D$ is a cyclic quadrilateral.. If $∠ B C D = 100^{o}$ and $∠ A B D = 70^{o}$ , find $∠ A D B$ .

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Solution

In cyclic quadrilateral

The sum of opposite angles is $180$

$⟹ ∠ A + ∠ C = 180 ∠ A = 180 - 100 = 80$

In $Δ A B D$

$∠ A D B + 80 + 70 = 180 ∠ A D B = 180 - 150 = 30$

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∠ B C D = 100^{o}

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ABCD is a cyclic quadrilateral. If $∠ B C D = 100^{\circ}$ and $∠ A B D = 70^{\circ},$ then find $∠ A D B .$

In the figure, ABCD is a cyclic quadrilateral, If $∠ B C D = 100^{\circ} a n d ∠ A B D = 70^{\circ}, f i n d ∠ A D B$

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