In the figure ∠PSQ=90∘,
PQ = 10 cm, QS = 6 cm & RQ = 9 cm.
Calculate the length of PR (in cm).
Given that,
∠PSQ=90∘,
PQ = 10 cm, QS = 6 cm and RQ = 9 cm.
In the right-angled triangle ΔPSQ,
PQ2=PS2+QS2
[By Pythagoras theorem]
102=PS2+62
⇒PS2=100−36
⇒PS2=64
⇒PS=8 cm
Now, in the right-angled triangle ΔPSR,
PR2=PS2+RS2
[By Pythagoras theorem]
PR2=82+152
[Since RS=RQ+QS=9+6=15]
⇒PR2=64+225
⇒PR2=289
⇒PR=17 cm