In the figure below- OP- OQ- OR and OS are four rays- Then- find - POQ - - - QOR - - - SOR - - - POS-3- 60-120-90-0-

The correct option is B 120^∘ ∠ POQ + ∠ QOR + ∠ SOR + ∠ POS = 360^∘ ....(the sum of the angles around a point = 360^∘) So, (∠ POQ + ∠ QOR + ∠ ...

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Right Angle Triangle

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Question

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

$60^{\circ}$

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$120^{\circ}$

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$90^{\circ}$

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$0^{\circ}$

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In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

In the figure below, OP, OQ, OR and OS are four rays.
Find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}

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