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Question

In the figure below, OP, OQ, OR and OS are four rays. Then, find ( POQ + QOR + SOR + POS)3.


A

60

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B

120

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C

90

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D

0

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Solution

The correct option is B

120


POQ + QOR + SOR + POS = 360 ....(the sum of the angles around a point = 360)
So, ( POQ + QOR + SOR + POS)3 = 3603 = 120


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