In the figure, $□ A B C D$ is a parallelogram. $A B = 8, B C = 12$ and $∠ B = 30^{o}$ . Find $A (□ A B C D)$ .

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Solution

Area of parallelogram $= a b sin θ$

$= 8 \times 12 \times sin 30^{\circ}$

$= 8 \times 12 \times \frac{1}{2}$

$= 4 \times 12$

$= 48$ sq.units

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In the figure, □ABCD is a parallelogram. AB=8,BC=12 and ∠B=30o. Find A(□ABCD).

Area of parallelogram =absinθ=8×12×sin30∘=8×12×12=4×12=48 sq.units

In the figure, $□ A B C D$ is a parallelogram. $A B = 8, B C = 12$ and $∠ B = 30^{o}$ . Find $A (□ A B C D)$ .

Area of parallelogram $= a b sin θ$

$= 8 \times 12 \times sin 30^{\circ}$

$= 8 \times 12 \times \frac{1}{2}$

$= 4 \times 12$

$= 48$ sq.units