Question

In the figure given ACD is a cyclic quadrilateral, find $\angle$BCD is

• A. ${255}^o$
• B. ${75}^o$
  
• C. ${105}^o$
• D. ${165}^o$

Answer 1

The correct option is B ${75}^o$

Sum of

$\because$ Opposite angles of a cyclic quadrilateral $={180}^0.$

$\therefore \angle DCB=\angle BCD={180}^0-{105}^0={75}^0.$