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Question
In the figure, given, below, AD ⊥ BC. then, c2=a2+b2−2ax.
If the above statement is true then mention answer as 1, else mention 0 if false
If the above statement is true then mention answer as 1, else mention 0 if false
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Solution
In △ABD,
c2=h2+(a−x)2
In △ABC,
b2=h2+x2
Subtracting both the equations:
c2−b2=h2+(a−x)2−h2−x2
c2=b2+a2+x2−2ax−x2
c2=a2+b2−2ax
c2=h2+(a−x)2
In △ABC,
b2=h2+x2
Subtracting both the equations:
c2−b2=h2+(a−x)2−h2−x2
c2=b2+a2+x2−2ax−x2
c2=a2+b2−2ax
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