In the figure given below, if π΄πΆ = π΄πΈ, π΄π΅ = π΄π·, and β π΅π΄π· = β πΈπ΄πΆ, then:
A
AB = AE
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B
AD = AC
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C
BC = DE
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D
BD = DE
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Solution
The correct option is C BC = DE In ΔABC and ΔADE
AB = AD [Given]
AC = AE [Given]
∠BAD = ∠EAC [Given] ---(i)
Adding ∠DAC on both side of the equation (i),
∠BAC = ∠DAE