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Question

In the figure given below, show that length AH>AB+BC+CD
569704_783d0fd762754befa43fe6b6046215e1.png

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Solution

AH=AB+BC+CD+DE+EF+FG+GH
AB+BC+CD is a part of AH
According to Euclid's fifth axiom the whole thing is greater then a part
AH>AB+BC+CD

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