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Question

In the figure given below, the current passing through 6 Ω resistor is


A
0.40 A
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B
0.48 A
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C
0.72 A
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D
0.80 A
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Solution

The correct option is B 0.48 A
PD across the circuit will be

V=i(R1R2R1+R2)=1.2×6×46+4

V=2.88 V

So, current through 6 Ω resistance will be

i1=VR=2.886=0.48 A

Alternative solution:

From current division law,

i1=i(R2R1+R2)

i1=1.2(46+4)=1.2(410)

i1=0.48 A

Hence, option (b) is correct.

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