Question

In the figure given below, the position-time graph of a particle of mass 0.1 Kg is shown. The impulse at t = 2 sec is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Velocity between t = 0 and t = 2 sec
$\Rightarrow v_i=\frac{dx}{dt}=\frac{4}{2}=2m/s$
Velocity at t = 2 sec, $v_f=0$
Impulse = Change in momentum = $m(v_f-v_i)$
$=0.1(0-2)=-0.2kgmse{c}^{-1}$