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Question

# In the given figure, the position-time graph of a particle of mass 0.1kg is shown. The impulse at t=2sec is:

A
0.2kg m sec1
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B
0.2kg m sec1
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C
0.1kg m sec1
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D
0.4kg m sec1
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Solution

## The correct option is B −0.2kg m sec−1Step 1: Initial velocity Velocity is given by the slope of the displacement-time graph.From t=0 to t=2s Slope =Displacementtime=4−02−0=2 ∴u=2m/s Step 2: Final velocity At t=2s, Slope of x−t graph is zero ∴v=0m/sStep 3: ImpulseImpulse is defined as change in momentum. I=m(v−u) =0.1kg×(0−2m/s) =−0.2kg m s−1Hence, Option(B) is correct.

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