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Question

In the figure given below, the position-time graph of a particle of mass 0.1 Kg is shown. The impulse at t = 2 sec is

A
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B
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C
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D
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Solution

The correct option is B
Velocity between t = 0 and t = 2 sec
vi=dxdt=42=2 m/s
Velocity at t = 2 sec, vf=0
Impulse = Change in momentum = m(vfvi)
=0.1(02)=0.2 kg m sec1

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