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Common Rays in Thin Lenses

In the figure...

Question

In the figure given below, there are two convex lens $L_{1}$ and $L_{2}$ having focal length of $f_{1}$ and $f_{2}$ respectively. The distance between $L_{1}$ and $L_{2}$ will be

f_{1}

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f_{2}

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f_{1} + f_{2}

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f_{1} - f_{2}

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Solution

The correct option is C $f_{1} + f_{2}$
For $L_{1}$ , rays are coming from infinity and hence, image is formed at focus.
$v_{1} = f_{1}$

For $L_{2}$ , rays after refraction, become parallel to principal axis. Hence, object for second lens is at its focus.
$u_{2} = f_{2}$

Distance between the lenses from the diagram given in the problem is:
$L = v_{1} + u_{2} = f_{1} + f_{2}$

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In the figure given below, there are two convex lens L1 and L2 having focal length of f1 and f2 respectively. The distance between L1 and L2 will be

In the figure given below, there are two convex lens $L_{1}$ and $L_{2}$ having focal length of $f_{1}$ and $f_{2}$ respectively. The distance between $L_{1}$ and $L_{2}$ will be