Question 4 then - AOC is equal toA 20-B 40-C 60-D 10-

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Question 4 th...

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Question 4
In the figure, if $∠ A B C = 20^{\circ}$ , then $∠ A O C$ is equal to

(A) 20º
(B) 40º
(C) 60º
(D) 10º

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∠ A B C = 20^{\circ}

∠ A O C

20^{\circ}

40^{\circ}

60^{\circ}

10^{\circ}

∠ A B C = 20^{\circ}

∠ A O C

20^{\circ}

40^{\circ}

60^{\circ}

10^{\circ}

Question 19

In the given figure, BC = CA and $∠ A = 40^{\circ}$ . Then, $∠ A C D$ is equal to

a) $40^{\circ}$
b) $80^{\circ}$
c) $120^{\circ}$
d) $60^{\circ}$

∠ O A B = 40^{\circ}

∠ A C B

50^{\circ}

40^{\circ}

60^{\circ}

70^{\circ}

∠ O A B = 40^{\circ}

∠ A C B

50^{\circ}

40^{\circ}

60^{\circ}

70^{\circ}

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