Question

In the figure, if $\angle ACB={35}^{\circ }$, then find the measure of $\angle OAB$.

Answer 1

$\angle AOB=2\angle ACB=2\times 35={70}^{\circ }$

ln $\Delta AOB\Rightarrow \angle A=\angle B$

(Angles opposite to equal sides)

$\therefore \angle A+\angle B+\angle O={180}^{\circ }$

$2\angle A+{70}^{\circ }={180}^{\circ }$

$\angle A={55}^{\circ }=\angle OAB$