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In the figure intensity from each slit S1, S2 and S3 is I0 at P. Wavelength of light is λ (D >> d)
List - 1 gives some values and List - 2 gives corresponding intensity at P. If space between slits and screen is filled with fluid of refractive index 32 then correct match is
List-1List-2Id2D=λPI0IId2D=λ2Q4I0IIId2D=1.5λR5I0IVd2D=2λS9I0T3I0UNone

A
IP, IIR, IIIS, IVU
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B
IR, IIP, IIIP, IVP
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C
IP, IIR, IIIT, IVS
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D
IP, IIR, IIIP, IVS
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Solution

The correct option is B IR, IIP, IIIP, IVP
IR, IIP, IIIU, IVP

Δϕ=2πλΔxoptical

Δx23=2d2Dμ, Δx13=92d2Dμ

I) ϕ23=4π×32=6π and ϕ13=9π×32=272πI=5I0

II) ϕ23=2π×32=3π and ϕ13=9π2×32=274πI=I0

III) ϕ23=9π and ϕ13=814πI=I0

IV) ϕ23=8π×32=12π and ϕ13=18π×32=27πI=I0

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