Question

In the figure (not drawn to scale), $ADF$ and $DEF$ are triangles and $EC=ED$, find $y$

• A. ${90}^o$
• B. ${91}^o$
• C. ${92}^o$
• D. ${93}^o$

Answer 1

The correct option is A ${90}^o$

In $△CED$, we have

$CE=ED$ .....Given
$\therefore \angle EDC=\angle ECD$
(Angles opposite to equal sides are equal)
$\Rightarrow \angle ECD={28}^o$
Also, $\angle ECD=\angle BCA$ (Vertically opposite angles)
$\Rightarrow \angle BCA={28}^o$
In $△BCA,y={62}^o+{28}^o$ (Exterior angle property)
$\Rightarrow y={90}^o$