Question

In the figure, O is the center of the circle, AB = CD and $\angle$ABO = ${35}^{\circ }$. Then the value of $\angle$DCO is ${35}^{\circ }$

• A. 35
• B. False

Answer 1

The correct option is A

35

OB = OC (Radii of the same circle)

OA = OD (Radii of the same circle)

AB = CD (Given)

$△$AOB $\cong$ $△$ DOC (By SSS congruence condition)

So, $\angle$ABO = $\angle$DCO = ${35}^{\circ }$(Corresponding parts of congruent triangles)