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Byju's Answer

Standard XII

Chemistry

Introduction

In the figure...

Question

In the figure, point B lies in the interior of circle, so

O B > R

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O B < R

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O B = R

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none of these

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Solution

The correct option is A $O B < R$
The interior of a circle is the set of all points whose distance from the center of the circle is less than the length of the radius of the circle
In given figure point B lies in the interior of circle
And OA is the radius of circle R
Then $O B < O A$ or $O B < R$

Suggest Corrections

Similar questions

In the figure, AC is tangent to the circle at O and CB is is the perpendicular from C to O. If the radius of the circle is r, then, select the statement that is true.

Q. Assertion :The resultant of the three vector

\to O A, \to O B

and

\to O C

as shown in the figure is

R (1 + \sqrt{2})

.Here

R

is the radius of the circle.(Here

∠ A O B = ∠ B O C = 45^{\circ}

) Reason:

\to O A + \to O C

is along

\to O B

and

(\to O A + \to O C) + \to O B

is along

\to O B

Q. O is any point in the interior of ∆ABC. Then, which of the following is true?
(a)

(O A + O B + O C) > (A B + B C + C A)

(b)

(O A + O B + O C) > \frac{1}{2} (A B + B C + C A)

(c)

(O A + O B + O C) < \frac{1}{2} (A B + B C + C A)

(d) None of these

Q. Find the resultant of three vectors

- - \to O A, - - \to O B a n d - - \to O C

shown in figure. Radius of circle is 'R'.

Q. O is a point that lies in the interior of

Δ A B C

. Then

2 (O A - O B - O C) > Perimeter o f Δ A B C

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In the figure, point B lies in the interior of circle, so

The correct option is A OB<RThe interior of a circle is the set of all points whose distance from the center of the circle is less than the length of the radius of the circleIn given figure point B lies in the interior of circle And OA is the radius of circle RThen OB<OA or OB<R

The correct option is A $O B < R$
The interior of a circle is the set of all points whose distance from the center of the circle is less than the length of the radius of the circle
In given figure point B lies in the interior of circle
And OA is the radius of circle R
Then $O B < O A$ or $O B < R$