Question

In the figure, $PQ=RS$ and $\angle ORS={48}^{\circ }$ Find $\angle OPQ$ and $\angle ROS.$

Answer 1

Both triangle POQ and ROS are same with three equal side and are isosceles

triangle.

$\begin{array}{c}\angle ORS=\angle OSR=\angle OPQ\angle OQP={48}^0\\ Hence\\ \angle ROS=180-\angle OSR+\angle ORS\\ =180-48+48\\ ={84}^0\end{array}$

Since two sides of both triangles are radius of circle

Hence, these sides are equal and given the base of both triangle are equal.