In the figure, $S_{1} a n d S_{2}$ are identical springs. The oscillation frequency of the mass m is f. If one spring is removed, the frequency will become

No worries! We‘ve got your back. Try BYJU‘S free classes today!

fx2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D

For the given figure f = $\frac{1}{2 π} s q r t \frac{k_{e q}}{m} = \frac{1}{2 π} \sqrt{\frac{2 k}{m}}$ ....(i)

If one spring is removed , then $k_{e q}$ = k and

$f = \frac{1}{2 π} \sqrt{\frac{k}{m}}$ ......(ii)

From equation (i) and (ii), $\frac{f}{f^{'}} = \sqrt{2} \Rightarrow f^{'} = \frac{f}{\sqrt{2}}$

Suggest Corrections

Similar questions

Q. In the fig.

S 1

and

S 2

are identical springs. The oscillation frequency of mass

m

f

. If one spring is removed, the frequency will become

S_{1}

and

S_{2}

are two identical springs. The oscillation frequency is

f

. If one spring is removed, frequency will be

Q. For the given experimental setup, the oscillation frequency of the mass is

f . S_{1}

and

S_{2}

are identical springs. One spring is now removed, then frequency will become.

Q. A mass

m

is suspended from a spring. Its frequency of oscillation is

f

. The spring is cut into equal halves and the same mass is suspended from one of the two pieces of the spring. The frequency of oscillation is the mass will be

A block of mass m is suspended from a spring. Its frequency of oscillation is f. The spring is cut into two identical halves and the same block is suspended from one of the two pieces of the spring such that it just touches the other spring below in its equilibrium position. The frequency of small oscillations of the mass will be

Join BYJU'S Learning Program

In the figure, S1 and S2 are identical springs. The oscillation frequency of the mass m is f. If one spring is removed, the frequency will become

The correct option is D For the given figure f = 12π sqrtkeqm=12π√2km ....(i) If one spring is removed , then keq = k and f=12π√km ......(ii) From equation (i) and (ii), ff′=√2⇒f′=f√2

In the figure, $S_{1} a n d S_{2}$ are identical springs. The oscillation frequency of the mass m is f. If one spring is removed, the frequency will become