In the figure shown, battery 1 has emf=6V and internal resistance = 1 Ω. Battery 2 has emf = 2V and internal resistance = 3 Ω. The wires have negligible resistance. What is the potential difference across the terminals of battery 2 ?
A
4 V
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B
1.5 V
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C
5 V
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D
0.5 V
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Solution
The correct option is C 5 V Applying KVL in the given loop.
⟹−V2+3I+V1+I=0
⟹−2+6+4I=0
I=−44=1
Now potential difference across terminal of battery 2 is C2