In the figure shown, battery 1 has emf = 6V, internal resistance =1Ω. Battery 2 has emf = 2V and internal resistance =3Ω. The wires have negligible resistance. What is the potential difference across the terminals of battery 2?
A
4V
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B
1.5V
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C
5V
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D
0.5V
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Solution
The correct option is D5V Using KVL, 6−2=(1+3)I or I=1A
Thus terminal potential of battery 2 is V2=2+3I=2+3=5V