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Question

In the figure shown, battery 1 has emf=6V and internal resistance = 1 Ω.
Battery 2 has emf = 2V and internal resistance = 3 Ω. The wires have
negligible resistance. What is the potential difference across the terminals
of battery 2 ?

41450_c687182e5373457b94961e4be1bafe1c.png

A
4 V
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B
1.5 V
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C
5 V
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D
0.5 V
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Solution

The correct option is C 5 V
Applying KVL in the given loop.
V2+3I+V1+I=0
2+6+4I=0
I=44=1
Now potential difference across terminal of battery 2 is C2
C2=V23I=23(1)=5V

1030997_41450_ans_aeea67b2e9ec479f98966136d1d808b5.png

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