Question

In the figure shown below, all the op amps are ideal,

The output voltage $V_0$ is __ V.

• A. -17

Answer 1

The correct option is A -17

Now, $I_1=\frac{4-2}{2k}=1mA$

$V_{01}=(4+3)$ (By using KCL equation)

= 7 V

$V_{02}=-1V$

$\therefore V_0=\left(\frac{-10}{5}\right)\times 7+(1+\frac{10}{5})\times (-1)$

= -14 - 3 = -17 V