Question

In the figure shown below, the voltage $V_0$ is

• A. $-|V_{m}sin\left(\omega t\right)|$
• B. $2V_m$
• C. $-2V_m$
• D. $|V_{m}sin\left(\omega t\right)|$

Answer 1

The correct option is B $2V_m$



Given circuit is voltage doubler circuit. Hence output $V_o$ will be doubled to that of input i.e. $2V_m$