In the figure shown, find the tension T1 (in N) in the string. Assume the strings to be inextensible and pulley frictionless.
A
2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.5g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D4g The given arrangement is shown in the below figure.
Consider 2kg and 3kg masses as a system and let the acceleration of the entire system is given by a.
From the FBD of 10kg mass and combined mass of 2kg and 3kg, we get 10g−T=10aT−5g=5a5g=15aa=g3m/s2
From the FBD of 3Kg mass we have
From the FBD of 3kg mass, T1−3g=3a⇒T1=3(g+a)=3(g+g3)
Thus, T1=4gN