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Question

In the figure shown ground is smooth, whereas surface between 10kg block and 5 kg block is rough. A force of magnitude 30 N is applied on 10 kg block, horizontally. If net work done by friction on the system (on 10 kg and 5 kg blocks) in any time frame is zero, then coefficient of friction between 10 kg and 5 kg can be
1130082_c380fdc0505d4c3d90cf7170df326c98.png

A
0.2
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B
0.3
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C
0.4
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D
0.6
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Solution

The correct option is A 0.2
Since there is no work done by friction, there is no relative motion between the blocks.
Hence , for 10 kg block,
30f=10a
For 5 kg block,
5a=f
30=15a
a=2ms2
f=μmgf=12×5×10f=0.2

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