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Question

# In the figure shown B1,B2 and B3are the three bulbs rated as (200 V,25 W ) respectively. Which bulb will give more light?

A
B1
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B
B2
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C
B3
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D
All three will give equal light
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Solution

## The correct option is C B3Using the relation P=v2Rfor power rating of each bulb. R1=(V)2P1=(200)250=800 Ω R2=(V)2P2=(200)2100=200 Ω R3=(V)2P3=(200)225=1600 Ω All the three bulbs are in series thus current supplied by battery, i=VReq=200R1+R2+R3 Also same current will pass through each bulb. Using relation for power consumed by bulb, P=i2R.......(i) ∵R3>R1>R2 and i1=i2=i3=i From Eq.(i)we get, P∝R ⇒P3>P1>P2 Power consumed by bulb B3 is maximum hence it will glow the brightest. ∴B3 will give more light.

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