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Question

In the figure shown the man of mass 60kg is lowering a block of mass 10kg with an acceleration of 2m/s2. Find the reading of the machine.
1120667_e2038051f443484d8d646d0e6cfde100.png

A
58kg
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B
68kg
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C
78kg
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D
88
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Solution

The correct option is C 78kg

mgT=ma,

10×1010×2=T

T=9820

T=78kg

This is the reading I m/c


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